Molar solutions

Type :

Term papers

Pages :

9 pages

Format :

.doc

Published date :

09/04/2009

Category :

Science & technology

Sub category :

Physics & chemistry

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Summary :

Introduction
Changes in the volume of the reactant
The mole ratio formula
Calculating the amount of precipitate
Materials for experiment
The procedure
Observation
Experimental errors
Conclusion

Abstract

Before the experimenting phase of the lab, the students must first calculate the molarity of the given solutions so that exact reacting ratio will occur between the two solutions when mixed. One reactant will be constant, as in each lab the molarity and the volume of that reactant will remain the same. The other reactant, however, will vary. The volume of the reactant will change during every reaction for it's the independent variable in the lab and the objective of this lab is to study how the change in molarity affects the amount of product that will form. The product is the substance that forms from the reaction of the two reactants. Some information is given, such as the molarity and volume of the constant reactants and the volume of the varying reactant. The problem is to calculate the unknown molarity of the varying reactant. But before any calculations should be done, the first concept that needs to be understood is 'exact reacting ratio'. Exact reacting ratio is when two solutions are combined, the ratio of moles are perfect so that both reactants will completely react. But if the mole ratio isn't perfect and the number of moles of each reactant has isn't proportional, then during the reaction, one of the chemicals will get used up before the other one.